PHP Functions
The real power of PHP comes from its functions.
PHP has more than 1000 built-in functions, and in addition you can create your own custom functions.
PHP Built-in Functions
PHP has over 1000 built-in functions that can be called directly, from within a script, to perform a specific task.
Please check out our PHP reference for a complete overview of the PHP built-in functions.
PHP User Defined Functions
Besides the built-in PHP functions, it is possible to create your own functions.
- A function is a block of statements that can be used repeatedly in a program.
- A function will not execute automatically when a page loads.
- A function will be executed by a call to the function.
Create a Function
A user-defined function declaration starts with the keyword function
, followed by the name of the function:
ExampleGet your own PHP Server
function myMessage() {
echo "Hello world!";
}
Note: A function name must start with a letter or an underscore. Function names are NOT case-sensitive.
Tip: Give the function a name that reflects what the function does!
Call a Function
To call the function, just write its name followed by parentheses ()
:
In our example, we create a function named myMessage()
.
The opening curly brace {
indicates the beginning of the function code, and the closing curly brace }
indicates the end of the function.
The function outputs "Hello world!".
PHP Function Arguments
Information can be passed to functions through arguments. An argument is just like a variable.
Arguments are specified after the function name, inside the parentheses. You can add as many arguments as you want, just separate them with a comma.
The following example has a function with one argument ($fname)
. When the familyName()
function is called, we also pass along a name, e.g. ("Jani")
, and the name is used inside the function, which outputs several different first names, but an equal last name:
Example
function familyName($fname) {
echo "$fname Refsnes.<br>";
}
familyName("Jani");
familyName("Hege");
familyName("Stale");
familyName("Kai Jim");
familyName("Borge");
Try it Yourself »The following example has a function with two arguments ($fname, $year)
:
Example
function familyName($fname, $year) {
echo "$fname Refsnes. Born in $year <br>";
}
familyName("Hege", "1975");
familyName("Stale", "1978");
familyName("Kai Jim", "1983");
Try it Yourself »PHP Default Argument Value
The following example shows how to use a default parameter. If we call the function setHeight()
without arguments it takes the default value as argument:
Example
function setHeight($minheight = 50) {
echo "The height is : $minheight <br>";
}
setHeight(350);
setHeight(); // will use the default value of 50
setHeight(135);
setHeight(80);
Try it Yourself »PHP Functions - Returning values
To let a function return a value, use the return
statement:
Example
function sum($x, $y) {
$z = $x + $y;
return $z;
}
echo "5 + 10 = " . sum(5, 10) . "<br>";
echo "7 + 13 = " . sum(7, 13) . "<br>";
echo "2 + 4 = " . sum(2, 4);
Try it Yourself »Passing Arguments by Reference
In PHP, arguments are usually passed by value, which means that a copy of the value is used in the function and the variable that was passed into the function cannot be changed.
When a function argument is passed by reference, changes to the argument also change the variable that was passed in. To turn a function argument into a reference, the &
operator is used:
Example
Use a pass-by-reference argument to update a variable:
function add_five(&$value) {
$value += 5;
}
$num = 2;
add_five($num);
echo $num;
Try it Yourself »Variable Number of Arguments
By using the ...
operator in front of the function parameter, the function accepts an unknown number of arguments. This is also called a variadic function.
The variadic function argument becomes an array.
Example
A function that do not know how many arguments it will get:
function sumMyNumbers(...$x) {
$n = 0;
$len = count($x);
for($i = 0; $i < $len; $i++) {
$n += $x[$i];
}
return $n;
}
$a = sumMyNumbers(5, 2, 6, 2, 7, 7);
echo $a;
Try it Yourself »You can only have one argument with variable length, and it has to be the last argument.
Example
The variadic argument must be the last argument:
function myFamily($lastname, ...$firstname) {
txt = "";
$len = count($firstname);
for($i = 0; $i < $len; $i++) {
$txt = $txt."Hi, $firstname[$i] $lastname.<br>";
}
return $txt;
}
$a = myFamily("Doe", "Jane", "John", "Joey");
echo $a;
Try it Yourself »If the variadic argument is not the last argument, you will get an error.
Example
Having the ...
operator on the first of two arguments, will raise an error:
function myFamily(...$firstname, $lastname) {
$txt = "";
$len = count($firstname);
for($i = 0; $i < $len; $i++) {
$txt = $txt."Hi, $firstname[$i] $lastname.<br>";
}
return $txt;
}
$a = myFamily("Doe", "Jane", "John", "Joey");
echo $a;
Try it Yourself »PHP is a Loosely Typed Language
In the examples above, notice that we did not have to tell PHP which data type the variable is.
PHP automatically associates a data type to the variable, depending on its value. Since the data types are not set in a strict sense, you can do things like adding a string to an integer without causing an error.
In PHP 7, type declarations were added. This gives us an option to specify the expected data type when declaring a function, and by adding the strict
declaration, it will throw a "Fatal Error" if the data type mismatches.
In the following example we try to send both a number and a string to the function without using strict
:
Example
function addNumbers(int $a, int $b) {
return $a + $b;
}
echo addNumbers(5, "5 days");
// since strict is NOT enabled "5 days" is changed to int(5), and it will return 10
Try it Yourself »To specify strict
we need to set declare(strict_types=1);
. This must be on the very first line of the PHP file.
In the following example we try to send both a number and a string to the function, but here we have added the strict
declaration:
Example
<?php declare(strict_types=1); // strict requirement
function addNumbers(int $a, int $b) {
return $a + $b;
}
echo addNumbers(5, "5 days");
// since strict is enabled and "5 days" is not an integer, an error will be thrown
?>
Try it Yourself »The strict
declaration forces things to be used in the intended way.
PHP Return Type Declarations
PHP 7 also supports Type Declarations for the return
statement. Like with the type declaration for function arguments, by enabling the strict requirement, it will throw a "Fatal Error" on a type mismatch.
To declare a type for the function return, add a colon ( :
) and the type right before the opening curly ( {
)bracket when declaring the function.
In the following example we specify the return type for the function:
Example
<?php declare(strict_types=1); // strict requirement
function addNumbers(float $a, float $b) : float {
return $a + $b;
}
echo addNumbers(1.2, 5.2);
?>
Try it Yourself »You can specify a different return type, than the argument types, but make sure the return is the correct type:
Example
<?php declare(strict_types=1); // strict requirement
function addNumbers(float $a, float $b) : int {
return (int)($a + $b);
}
echo addNumbers(1.2, 5.2);
Try it Yourself »PHP Exercises
- Art
- Causes
- Crafts
- Dance
- Drinks
- Film
- Fitness
- Food
- Jeux
- Gardening
- Health
- Domicile
- Literature
- Music
- Networking
- Autre
- Party
- Religion
- Shopping
- Sports
- Theater
- Wellness